Conservative Fields
Conditions
- Clairaut’s Conditions are satisfied
∂y∂F1∂z∂F1∂z∂F2=∂x∂F2=∂x∂F3=∂y∂F3
- E is simply connected (no holes)
Properties
- ⟺F=∇f in E
- ⟺curlF=0 in simply connected E
- (⟹curlF=0 in E )
- ⟺
- Path Independent Line Integrals: ∫CF⋅dr=∫C′F⋅dr
- Circulation of F=0: ∮CF⋅dr=0 for C∈E
Potential
f(x,y,z)=∫x0xF1(t,y0,z0)dt+∫y0yF1(x,t,z0)dt+∫z0zF1(x,y,t)dt+C